(1/7)^x+3=1

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Solution for (1/7)^x+3=1 equation: 



(1/7)^x+3=1

We move all terms to the left:

(1/7)^x+3-(1)=0



Domain of the equation: 7)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/7)^x+3-1=0

We add all the numbers together, and all the variables

(+1/7)^x+2=0

We multiply all the terms by the denominator


(+1+2*7)^x=0

We add all the numbers together, and all the variables

15^x=0

x=0/1

x=0

Równanie nie ma rozwiązania

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